What is the heat exchange required to melt 1 pound of ice to water at 32°F?

What is the heat exchange required to melt 1 pound of ice to water at 32°F?

• A. 144 BTUs
• B. 200 BTUs
• C. 970 BTUs
• D. 500 BTUs

Answer: (A)

To determine the heat exchange required to melt 1 pound of ice at 32°F into water at the same temperature, we need to look at the concept of latent heat of fusion. The latent heat of fusion is the amount of energy required to change a substance from solid to liquid at its melting point, without changing its temperature. For ice, the latent heat of fusion is approximately 144 BTUs per pound. Therefore, when we want to convert 1 pound of ice at 32°F to water at 32°F, we need to supply 144 BTUs of heat to break the molecular bonds holding the ice in its solid form. This makes the first choice, which indicates 144 BTUs, the correct answer for the heat exchange needed to complete this phase change. Other answers that represent different values are not applicable to this specific process of melting ice at the given temperature.

To determine the heat exchange required to melt 1 pound of ice at 32°F into water at the same temperature, we need to look at the concept of latent heat of fusion. The latent heat of fusion is the amount of energy required to change a substance from solid to liquid at its melting point, without changing its temperature.

For ice, the latent heat of fusion is approximately 144 BTUs per pound. Therefore, when we want to convert 1 pound of ice at 32°F to water at 32°F, we need to supply 144 BTUs of heat to break the molecular bonds holding the ice in its solid form.

This makes the first choice, which indicates 144 BTUs, the correct answer for the heat exchange needed to complete this phase change. Other answers that represent different values are not applicable to this specific process of melting ice at the given temperature.